Calculate Electrical Conductivity
October 2nd, 2009
Write the equation for this reaction. Calculate the pH of the solution.?
A Solution contains 0.675 g of ethylamine, C2H5NH2, per 100.0 mL of solution. Electrical conductivity measurements at 20 C show that 0.90% of the ethylamine has reacted with water. Write the equation for this reaction. Calculate the pH of the solution.
C2H5NH2 + H2O C2H5NH3+ + OH-
moles C2H5NH2 = 0.675 g/45.0847 g/mol=0.0150
[C2H5NH2]= 0.0150/ 0.100 L= 0.150 M
[OH-]= [C2H5NH3+]= 0.150 x 90/100=0.135 M
pOH = 0.869
pH = 13.1
Emf electrical radiation pollution part 4 involving cell pho